This is a SyntaxError that confuses many beginners, especially if they are trying to format numbers neatly in their code. The message SyntaxError invalid decimal literal is a common error encountered when making a mistake in writing numbers in Python code.

It means: You tried to write a number that starts with a zero, but it isn’t a valid “octal” (base-8) number.

# WRONG — leading zero on a decimal integer crashes immediately
week_1_sales = 150
week_2_sales = 90
week_3_sales = 05    # SyntaxError: invalid decimal literal
week_4_sales = 09    # SyntaxError: invalid decimal literal

# WRONG — variable names starting with a number also fire this error
1st_place = "Alice"  # SyntaxError: invalid decimal literal

# RIGHT — remove the leading zero from the integer literal
week_3_sales = 5
week_4_sales = 9

# RIGHT — use f-string zero-padding when the output needs leading zeros
hour = 9
minute = 5
print(f"Time: {hour:02}:{minute:02}")    # Output: Time: 09:05

# RIGHT — valid non-decimal literals use explicit prefixes
octal   = 0o17    # octal — prefix 0o
hex_val = 0xFF    # hexadecimal — prefix 0x
binary  = 0b1010  # binary — prefix 0b

The Cause

In Python (and many other languages), a number starting with 0 is not treated as a normal “decimal” (base-10) number.

• 0o (zero-oh) means the number is Octal (base-8).
• 0x (zero-ex) means the number is Hexadecimal (base-16).
• 0b (zero-bee) means the number is Binary (base-2).

Problem Code: You are probably trying to align your numbers, like this:

week_1_sales = 150
week_2_sales = 90
week_3_sales = 05  # CRASH!

Error: SyntaxError: invalid decimal literal

Python sees 05 and thinks you might be trying to write an octal number (because of the 0), but it’s not a valid format. In modern Python 3, this is just disallowed to prevent confusion.

The Fix: Just Remove the Leading Zero

Numbers don’t need leading zeros for alignment.

week_1_sales = 150
week_2_sales = 90
week_3_sales = 5   # Correct!

If you are trying to print a number with leading zeros (for a report or a clock), you must do it with an f-string.

Correct Way to Format:

hour = 9
minute = 5

# Use :02 to mean "pad with 0s to be 2 digits wide"
print(f"The time is {hour:02}:{minute:02}")
# Output: The time is 09:05

SyntaxError: invalid decimal literal — Leading Zeros, Number Bases, and Zero-Padding in Python 3

SyntaxError: invalid decimal literal fires before Python runs a single line. The parser sees a 0 at the start of a number token and checks for a valid base prefix — 0o, 0x, or 0b. Finding raw digits instead, it stops immediately.

Two patterns trigger this error. Both have instant fixes.

A decimal integer with a leading zero. 05, 09, 007, 042 — all crash in Python 3. Remove the leading zero. The value is identical: 5, 9, 7, 42. Python 2 allowed leading zeros as octal notation — code ported from Python 2 triggers this error in Python 3 when a bare 0-prefixed number appears.

A variable name starting with a digit. 1st_place, 2nd_item, 3rd_score — Python identifiers must start with a letter or underscore. A name starting with a digit crashes at parse time as an invalid literal. Rename to first_place, second_item, third_score, or place_1, item_2, score_3.

Zero-padding belongs in the output layer, never in the source code. Use f-string format specifiers for every case where leading zeros appear in display output.

Clock and time display

print(f”{hour:02}:{minute:02}:{second:02}”) # Output: 09:05:03

Fixed-width ID numbers

order_id = 7
print(f”Order #{order_id:05}”) # Output: Order #00007

Numeric alignment in reports

for i, val in enumerate([5, 42, 100], 1):
print(f”Week {i:02}: {val:>6}”) # right-aligned, zero-padded week number

The :0Nd format spec — where N is the total width — handles every zero-padding case. The value stays a plain integer in your code. The display layer handles the formatting. That separation keeps the SyntaxError permanently out of your source file.